x^2-94x+1=0

Solution for x^2-94x+1=0 equation:

x^2-94x+1=0

a = 1; b = -94; c = +1;
Δ = b2-4ac
Δ = -942-4·1·1
Δ = 8832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8832}=\sqrt{64*138}=\sqrt{64}*\sqrt{138}=8\sqrt{138}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-94)-8\sqrt{138}}{2*1}=\frac{94-8\sqrt{138}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-94)+8\sqrt{138}}{2*1}=\frac{94+8\sqrt{138}}{2}
$